WebGiven an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15], target = 9, Because nums [0] + nums [1] = 2 + 7 = 9, return [0, 1]. Question: WebFeb 14, 2024 · 1 vector adj [] in a parameter list is another (IMHO bad) way to write vector* adj, so you have a pointer there. – Ulrich Eckhardt Feb 14, 2024 at 21:52 4 Don't make a function do multiple things (single responsibility principle). If the function is called print, it should only print. – JHBonarius Feb 14, 2024 at 21:55 Add a comment
c++ - Initialize inline vector of bool - Stack Overflow
WebJul 28, 2014 · Another solution that uses GCC internals for vector and is more efficient: #include #include #include using namespace std; int main () { vector b (10,0); b [2] = 1; b [4] = 1; auto p = b.begin ()._M_p; cout << *p << endl; } WebWrite the inOrder () function, which receives a vector of integers as a parameter, and returns true if the numbers are sorted (in order from low to high) or false otherwise. The program outputs "In order" if the vector is sorted, or "Not in order" if the vector is not sorted. botosi the man slayer
Vector in C++ STL - GeeksforGeeks
WebNov 16, 2024 · Your probleme come from the return type, you wan't to return a std::vector but you are actualy returning an int: return 0; To fix it, just change the return value 0 to a std::vector value or change your return type to int instead of std::vector. Share. Improve this answer. WebNov 27, 2024 · class Solution: def twoSum (self, nums: List [int], target: int) -> List [int]: seen = {} for j, num in enumerate (nums): i = seen.get (target-num, -1) if i != -1: return [i, j] seen [num] = j return [-1, -1] Share Improve this answer Follow edited Dec 25, 2024 at 11:57 Blastfurnace 18.3k 55 56 70 answered Dec 25, 2024 at 11:34 WebFeb 13, 2024 · bool containsDuplicate (vector& nums) { //check if the vector is empty if (nums.empty ()) return false; //sort the vector sort (nums.begin (), nums.end ()); int i = 0; int j = i+1; while (j haydon bridge bypass